Solutions to Take-Home Part of Math 317 Exam #1
ثبت نشده
چکیده
where the first inequality is an application of the triangle inequality, the second follows from (1) and (2), and the third from the choice of m. Therefore, since our choice of > 0 was arbitrary, we conclude that the subsequence (xnm)→ b. A similar argument using the sequence (zm) given by zm = inf{xm, xm+1, . . .} and the version of Lemma 1.3.7 suitable for infima (see Exercise 1.3.2, which you did as a warm-up for HW #2, Problem 1) yields a subsequence converging to a.
منابع مشابه
Cytokine responses andmath performance: The role of stereotype threat and anxiety reappraisals
• Female college students take a math exam described as gender-fair or gender-biased. • In one condition, participants directed to reappraise physiological arousal. • Performance on math exam and post-exam levels of the cytokine IL-6 were measured. • Reappraisal of physiological arousal buffers inflammatory responses to exam across conditions. • Reappraisal of arousal especially effective buffe...
متن کاملImproving the security of quantum exam against cheating
The security of quantum exam [Phys. Lett. A 350 (2006) 174] is analyzed and it is found that this protocol is secure for any eavesdropper except for the “students” who take part in the exam. Specifically, any student can steal other examinees’ solutions and then cheat in the exam. Furthermore, a possible improvement of this protocol is presented.
متن کاملExistence and Nonexistence of Global Positive Solutions to Nonlinear Diffusion Problems with Nonlinear Absorption through the Boundary
This paper deals with the existence and nonexistence of global positive solutions to ut = ∆ ln(1 + u) in Ω× (0,+∞), ∂ ln(1 + u) ∂n = √ 1 + u(ln(1 + u)) on ∂Ω× (0,+∞), and u(x, 0) = u0(x) in Ω. Here α ≥ 0 is a parameter, Ω ⊂ RN is a bounded smooth domain. After pointing out the mistakes in Global behavior of positive solutions to nonlinear diffusion problems with nonlinear absorption through the...
متن کاملMath 317 HW #5 Solutions
Proof. I intend to use the Monotone Convergence Theorem, so my goal is to show that (xn) is decreasing and bounded. To do so, I will prove by induction that, for any n ∈ {1, 2, 3, . . .}, 0 < xn+1 < xn < 4. Base Case When n = 1, we have that x1 = 3 and x2 = 1 4−3 = 1, so 0 < x2 < x1. Inductive Step Suppose 0 < xk+1 < xk < 4; our goal is to show that this implies that 0 < xk+2 < xk+1 < 4. Since ...
متن کاملذخیره در منابع من
با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید
عنوان ژورنال:
دوره شماره
صفحات -
تاریخ انتشار 2010